(x+1)^2/5-3(x+1)^1/5+2=0

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Solution for (x+1)^2/5-3(x+1)^1/5+2=0 equation: 



(x+1)^2/5-3(x+1)^1/5+2=0

We multiply all the terms by the denominator


(x+1)^2-3(x+1)^1+2*5=0

We add all the numbers together, and all the variables

(x+1)^2-3(x+1)^1+10=0

We move all terms containing x to the left, all other terms to the right

(x+1)^2-3(x+1)^1=-10

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